See Our New JEE Book on Amazon
A capacitor is a combination of two conductors separated by a thin insulating material (called the dielectric). It can be charged by connecting the two conductors to a battery. The charge required to create a potential difference of 1 Volt between its conducting plates is called the capacitance of the capacitor. In this demonstration we will make capacitors with kitchen utensils and measure their capacitance in many combinations.
You need two similar flat bottomed steel thalis, wooden carrom board coins, three similar steel glasses, polythene sheet, newspaper, LCR meter.
The capacitance shows a value in picofarads which increases when a newspaper is inserted in the air gap.
In the arrangement made with the thalis, the steel thalis are the two conductors and placing carrom board coins creates an air gap which acts as the dielectric. Hence the arrangement acts as a capacitor. Putting paper in the air gap increases the capacitance as the dielectric constant of paper is higher than that of air. Capacitance \(C\) of the capacitor is given by the expression $$ C=K\epsilon_0 A/d $$ where \(\epsilon_0\) is the permittivity of free space, \(A\) is the area of the conductors, \(d\) is the distance between the two plates and \(K\) is the dielectric constant of the dielectric between the conductors. For air \(K = 1\) and for paper \(K>1\).
In the arrangement made with steel glasses, the steel glasses are the two conductors and the polythene acts as a dielectric. Hence it becomes a capacitor. The capacitance \(C_2\) is almost half of \(C_1\) as the arrangement makes it a series combination of two almost identical capacitors. The capacitance \(C_3\) is double of \(C_1\) as the arrangement this time makes it a parallel combination of two capacitors.
The equivalent capacitance \(C_{eq}\) of \(N\) identical capacitors each of capacitance \(C\) is given by, \(C_{eq}= C/N\) in series combination and \(C_{eq} = NC\) in parallel combination.
Subscribe to our channel