See Our New JEE Book on Amazon
In screening round of National Anveshika Experimental Skills Test ( NAEST 2019 ), a question was asked on a moving toy train. The train moves with a constant speed on a track consisting of (a) straight portion and (b) curved portion. The student needs to assess the acceleration of the train and force on it. The problem statement reads:
Question:The toy train is moving at a constant speed. Choose the correct option(s)
Let us analyse the motion of the train on straight portion of the track. On a straight track, the direction of motion is constant. Thus, speed as well as the direction of motion is constant on the straight track. Hence, the velocity $\vec{v}$ of the train is constant and its acceleration is $\vec{a}=\mathrm{d}\vec{v}/\mathrm{d}t=\vec{0}$. By Newton's second law, $\vec{F}=m\vec{a}$, the net external force on the train (in the horizontal plane) is zero.
On the curved portion of the track, the direction of motion varies continuously as the train moves. Although speed is constant, the velocity is not constant because of change in direction of motion. Thus, the acceleration of the train is non-zero. The direction of acceleration is towards the centre of curvature of the track. This acceleration is called centripetal acceleration. By Newton's second law, there is non-zero external force on the train as it moves on the curved path. This force is called centripetal force. This force is provided by the track and it acts at the contact point of the outer wheel.
The option (D) is also interesting. From the video, it appears that the train moves faster on the curved path as compared to that on the straight path. Since faster or slower depends on the speed of the train, which is given as constant, this option is rejected because it contradicts the problem statement. In many scenario, it is difficult to judge the speed by seeing a moving object. One such scenario is motion of the trees when looking from the window of a moving train.